Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorShare with your friendsAnswer (1 of 2) For the homogeneous equation (x^2 2y^2)dx (4xy y^2)dy =0 take y = xV(x) so dy = Vdx xdV The equation becomes (1 6V^2 V^3)dx x(4V V^2)dV =0 Separating (3V^2 12V)dV/3(v^3 6V^2 1) = dx/x or (1/3)d(V^3 6V^2 1) = dx/x Integrating ln(V^3 6V^2
A Opq Is Formed By The Pair Of Straight Lines X 2 4xy Y 2 0 And The Line Pq The Equation Of Pq Is X Y 2 0 Sarthaks Econnect Largest Online Education Community
(x+y)^2-4xy formula
(x+y)^2-4xy formula-The differential equation (2xy y^2 y) dx (3x^2 4xy 3x) = 0 is Exact and NonHomogeneous Exact and Homogeneous NonExact and Homogeneous NonExact and NonHomogeneous Solve x dy y dx = 2xy^2 dx x^3 = cy O x^3 y =c O x^3 = cy^2 O x^3 y^2 =c 21A an equilateral triangle B a right angled triangle C an isosceles triangle D None of these Answer A Solution Acute angle between the lines x^24xyy^2=0 is tan^2 (2sqrt (41))// (11)=tan^ (1)sqrt (3)=tan^ (1)pi//3 Angle bisectors of x^24xyy^2=0 are given by (x^2y^2)/ (11)= (xy)/ (2) x^2y^2=0rArr x=y As xy=0
Canonical form of a double hyperboloidNote We don't even have to consider the formula (xy)^2 = (xy)^24xy as in other problems and then find (xy) for solving the values of x and y because from (*) we have already concluded that one of x or y is ZERO and so if we take y= 0 and put it in (2),we get (it orally even) that x=3The joint (combined) equation of the lines OA and OB is x 2 4xy y 2 = 0 and the equation of the line AB is 2x 3y 1 = 0 ∴ points A and B satisfy the equations 2x 3y 1 = 0 and x 2 4xy y 2 = 0 simultaneously We eliminate x from the above equations, ie, put x = `(1
Description for Correct answer \( \Large cos^{2} \theta =\frac{(xy)^{2}}{4xy} \) max value of \( \Large cos^{2} \theta =1 \) \( \Large \Rightarrow 1=\frac{(xy)^{2Here $M= x^24xy2y^2 $ & $ N= y^24xy2x^2 $ $\dfrac {\partial M}{\partial y}=04x4y$ $\dfrac {\partial N}{\partial x}=04y4x$ Here, $\dfrac {\partial M}{\partial Use the quadratic formula to solve the equation for (a) x in terms of y and (b) y in terms of x Homework Equations 4x^2 4xy 1 y^2 = 0 The Attempt at a Solution I am not really sure where to start at all If I could just figure out the values for a, b, and c of the quadratic formula then the rest would be simple (for me)
Your differential equation is of the form M (x,y) dx N (x,y) dy = 0 with dN/dx = dM/dy (those being partial derivatives) The last equation is a necessary and sufficient condition for a solution of the form f (x,y) = 0 In your case df/dx (partial) = x^2 4xy 2y^2 andX 2 y 2 = (x – y) 2 2xy Algebraic identities The algebraic equations which are valid for all values of variables in them are called algebraic identities Factorise (x y)^24xy9z^2 (4 • (x 2)) 3 2 y 2 Step 2 Equation at the end of step 2 2 2 x 2 3 2 y 2 Step 3 Trying to factor as a Difference of Squares 31 Factoring 4x 29y 2 Favorite Answer x^2xy y^2 this equation can't be factor because there is no two numbers whose product and sum is one RealArsenalFan Lv 4 1 decade ago You
Please be sure to answer the questionProvide details and share your research!Combine 2xy and 4xy to get 2xy x^ {2}\left (2y\right)xy^ {2}=0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, one when ± is addition and one when it is subtractionTranscribed image text Find the general solution in powers of x of the differential equation (x^2 1)y" 4xy' 2y = 0 Assume the form y(x) = Sigma^infinity _n = 0 c_nx^n Then y'(x) = Sigma^infinity _n = 1 c_nx^n1 y"(x) = Sigma^infinity _n = 2 c_nx^n2 x^2y"(x) = Sigma^infinity _n = 2 c_nx^n y"(x) = Sigma^infinity _n = 0 c_nx^n 4xy'(x) = Sigma^infinity _n = 1 c_nx^n 2y(x) =
Write the equation x 2 4xy y 2 3 = 0;Answer by AnlytcPhil (1761) ( Show Source ) You can put this solution on YOUR website! Pair of Linear Equations in Two Variables (xy)2 = (xy)2 4xy how ?
Other calculators Graph of implicit function;(one minus x)y two strokes of the second (2nd) order minus 4xy stroke first (1st) order plus 5y stroke first (1st) order equally co sinus of e of x Similar expressions y'cosx2ycosx=2sinxSolve the following system of equations 3x 4xy 2y = 2 3x 2y = 10 Solve the second equation for either of the unknowns I'll pick x 3x 2y = 10 add 2y to both sides 3x = 10 2y Divide both sides by 3 x = (10 2y)/3 factor out 2 x = 2 (5 y
y = arctan(x)/(1x^2)^2 C/(1x^2)^2 We have (1x^2)y'4xy=(1x^2)^2 A We can rearrange A as follows (1x^2)y'4xy = 1/(1x^2)^2 dy/dx (4x)/(1x^2)y = 1/(1x^2)^3 B We can use an integrating factor when we have a First Order Linear nonhomogeneous Ordinary Differential Equation of the form;Can you see the Eiffel Tower from London? If 2x – y = , then the triangles is 6 If sinθ−cosθ s i n θ − c o s θ = 1 2 1 2 then value of sinθcosθ s i n θ c o s θ is 7 If sinθ cosθ = 1, then the sinθ cosθ is equal to 8 The angle of elevation of the top of a tower from two horizontal points (in opposite sides) at distances of x meter and x 12 meter from the
Thanks for contributing an answer to Mathematics Stack Exchange! Please see below The equation given here x^24xy4y^25sqrt51=0 is of the form Ax^2BxyCy^2DxEyF=0 What a rotation does is it changes x & yaxes to x' & y'axes, as shown below, In such a case, the relation between coordinate (x,y) and new coordinates (x',y') is given by x=x'costhetay'sintheta and y=x'sinthetay'costheta and reverse isSolution for x^24xy3y^2= equation Simplifying x 2 4xy 3y 2 = 0 Reorder the terms 4xy x 2 3y 2 = 0 Solving 4xy x 2 3y 2 = 0 Solving for variable 'x' Factor a trinomial (x y)(x 3y) = 0 Subproblem 1 Set the factor '(x y)' equal to zero and attempt to solve Simplifying x y = 0 Solving x y = 0 Move all terms containing x to the left, all other terms to the right
M = x 2 4xy 2y 2, N = y 2 4xy 2x 2 dM/dy = 4x 4y dN/dx = 4y 4x Therefore, dM/dy = dN/dx So, the given differential equation is exact On integrating M wrt x, treating y as a constant, On integrating N wrt y, treating x as a constant, (omitting 2xy 2 2x 2 y which already occur in ∫M dx) Therefore, the solution ofAnswer (1 of 4) y' = x 4xy Here are two basic methods to solve first order differential equations I'd choose separation of variables to solve this one more quickly 1 linear first order DE y' 4xy = x, \rho(x) = exp(\int 4x dx) = e^{2x^2} 2 separation of variables DE \frac{dy}{dx} =Surface defined by equation;
Bx" yp = Use reduction of order to find the general solution in this form (your answer will involve A, B, and x) y (2) =Related Links sec h (πi) cosec h (π / 2)i = sec 2 (tan1 2) cosec 2 (cot1 3) = Select the right option in the following Set A has m elements and set B has n elements If the total number of subsets of A is 112 more than the total number of subsets of B, then the value of m×n isIf the equation 2x^2 4xy 7y^212x2yt=0 where "t' is a parameter has exactly one real solution of the form (x,y)Then the sum of (xy) =?
Example 1 Determine the critical points and locate any relative minima, maxima and saddle points of function f defined by f(x , y) = 2x 2 2xy 2y 2 6x Solution to Example 1 Find the first partial derivatives f x and f y f x (x,y) = 4x 2y 6 f y (x,y) = 2x 4y The critical points satisfy the equations f x (x,y) = 0 and f y (x,y) = 0 simultaneously HenceSolve the equation Solution This is a Bernoulli equation with the parameter Therefore, we make the substitution The derivative is given by Multiply both sides of the original equation by and divide by Notice that in dividing by we have lost the solution Rewriting the last equation in terms of we get This differential equation is linear, soSolution(By Examveda Team) $$\eqalign{ & {\cos ^2}\theta = \frac{{{{\left( {x y} \right)}^2}}}{{4xy}} \cr & {\text{Max value of }}{\cos ^2}\theta = 1 \cr
Thanks for contributing an answer to Mathematics Stack Exchange! First we have to solve the homogeneous equation (31) x 2 y" − 4xy' 6y = 0 This is an EulerCauchy equation, so we look for solutions of the form y = x mThe characteristic equation for m is∴ x 2 4xy y 2 = 0 is the joint equation of the two lines through the origin each making an angle of 60° with x y = 10 ∴ x 2 4xy y 2 = 0 and x y = 10 form a triangle OAB which is equilateral
Find an answer to your question factorise X^2 4xy 4y^2 9z^2 AnshuSingh AnshuSingh 1 week ago Mathematics High School answered Factorise X^2 4xy 4y^2 9z^2 1 See answer AdvertisementX24xy4y2 Final result (x 2y)2 Step by step solution Step 1 Equation at the end of step 1 ( (x2) 4xy) 22y2 Step 2 Trying to factor a multi variable polynomial 21 Proof that x^24xyy^2=1 has infinitely many integer solutions Proof that x2 4xyy2 = 1 has infinitely many integer solutions https//mathstackexchangecomY'4xy^2=x Derivatives First Derivative Specify MethodNew Chain Rule Product Rule Quotient Rule Sum/Diff Rule Second Derivative Third Derivative Higher Order Derivatives Derivative at a point Partial Derivative Implicit Derivative Second Implicit Derivative Derivative using Definition Derivative Applications Tangent Normal Curved Line Slope
Please be sure to answer the questionProvide details and share your research!Examine the function f (x,y) = y2 4xy 3x2 x3 for extreme values written 10 months ago by teamques10 ♣ 16k modified 3 months ago by binitamayekar ♣ 25k engineering mathematics ADD COMMENT EDIT 1 Answer Find dy/dx by implicit differentiation x2 − 4xy y2 = 4 x24xyy2=4 Maybe you like Identify the surface whose equation is given?
Simplifying X 2 4xy y 2 = 0 Solving X 2 4xy y 2 = 0 Solving for variable 'X' Move all terms containing X to the left, all other terms to the right Add '4xy' to each side of the equationThe equation x y = 4 and x^2 4xy y^2 = 0 represent the sides of Question The equation x−y=4 and x 24xyy 2=0 represent the sides of A an equilateral triangle B a right angled triangle C an isosceles triangle D none of these Medium Solution Verified by Toppr Correct option is A an equilateral triangle Given sides x 24xyy 2=0⇒y 24xyx 2=0θ = 45° in terms of a rotated x′y′system using θ, the angle of rotation Write the equation involving x′ and y′ in standard form
(xy)^2 (xy)^2=4xy identity is the equation?Hello student, Pl Book a Trial With Our ExpertsClick here👆to get an answer to your question ️ The equation x^2 4xy 4y^2 3x 6y 4 = 0 represents a Solve Study Textbooks Guides Join / Login Question The equation x 2 4 x y 4 y 2 The equation λ x 2 4 x y y 2
Popular Problems Calculus Find dy/dx x^24xyy^2=13 x2 4xy y2 = 13 x 2 4 x y y 2 = 13 Differentiate both sides of the equation d dx (x2 4xy y2) = d dx (13) d d x ( x 2 4 x y y 2) = d d x ( 13) Differentiate the left side of the equation Tap for more steps DifferentiateBut avoid Asking for help, clarification, or responding to other answersExplanation Step 1 1 of 5 (a) We can detect the linear dependency of the functions by graphing them \\\\ all on the coordinate axes, and see if they are multiple of each other or not \\\\ Below are the graphs of both the functions y 1 = x 3 \\\\ {\color {#c} y_1=x^3}\quad y 1 = x 3
Given yı (2) = x² satisfies the corresponding homogeneous equation of = z'y" – 4xy' by = 6x – 12, x > 0 Then the general solution to the nonhomogeneous equation can be written in the form y (x) = Ax?Write logically 2 See answers Advertisement Brainly User Hello user Expanding the LHS we get (xy)^2 (xy)^2 x^2y^2 2xy x^2y^2 2xy 4xy =RHS Hence proved Advertisement harendrachoubay , verified Stepbystep explanation We have, Verify, LHS Using algebraic identity, and = 4xyBut avoid Asking for help, clarification, or responding to other answers
Answer x^24y^2=4xy x^24y^24xy=0 Using the formula (ab)^2=a^2b^22ab here a=x,b=2y so, (x2y)^2=0 x2y=0 x=2y x/y=2/1समीकरण `lamda x ^(2) 4xy y ^(2) lamda x 3y 2=0` परवलय निरूपित करता है यदि `lamda ` का मान है If 2x^2lambdax y^2y^2(lambda4)x6y5=0,Dy/dx P(x)y=Q(x) So we form an Integrating Factor;
Canonical form of a elliptical paraboloid;
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